Optimal. Leaf size=193 \[ \frac {i c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{16 \sqrt {2} a^3 f}+\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac {i c^4 \sqrt {c-i c \tan (e+f x)}}{4 a^3 f (c+i c \tan (e+f x))^2}+\frac {i c^3 \sqrt {c-i c \tan (e+f x)}}{16 a^3 f (c+i c \tan (e+f x))} \]
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Rubi [A]
time = 0.15, antiderivative size = 193, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 6, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {3603, 3568, 43,
44, 65, 212} \begin {gather*} \frac {i c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{16 \sqrt {2} a^3 f}-\frac {i c^4 \sqrt {c-i c \tan (e+f x)}}{4 a^3 f (c+i c \tan (e+f x))^2}+\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}+\frac {i c^3 \sqrt {c-i c \tan (e+f x)}}{16 a^3 f (c+i c \tan (e+f x))} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 44
Rule 65
Rule 212
Rule 3568
Rule 3603
Rubi steps
\begin {align*} \int \frac {(c-i c \tan (e+f x))^{5/2}}{(a+i a \tan (e+f x))^3} \, dx &=\frac {\int \cos ^6(e+f x) (c-i c \tan (e+f x))^{11/2} \, dx}{a^3 c^3}\\ &=\frac {\left (i c^4\right ) \text {Subst}\left (\int \frac {(c+x)^{3/2}}{(c-x)^4} \, dx,x,-i c \tan (e+f x)\right )}{a^3 f}\\ &=\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac {\left (i c^4\right ) \text {Subst}\left (\int \frac {\sqrt {c+x}}{(c-x)^3} \, dx,x,-i c \tan (e+f x)\right )}{2 a^3 f}\\ &=\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac {i c^4 \sqrt {c-i c \tan (e+f x)}}{4 a^3 f (c+i c \tan (e+f x))^2}+\frac {\left (i c^4\right ) \text {Subst}\left (\int \frac {1}{(c-x)^2 \sqrt {c+x}} \, dx,x,-i c \tan (e+f x)\right )}{8 a^3 f}\\ &=\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac {i c^4 \sqrt {c-i c \tan (e+f x)}}{4 a^3 f (c+i c \tan (e+f x))^2}+\frac {i c^3 \sqrt {c-i c \tan (e+f x)}}{16 a^3 f (c+i c \tan (e+f x))}+\frac {\left (i c^3\right ) \text {Subst}\left (\int \frac {1}{(c-x) \sqrt {c+x}} \, dx,x,-i c \tan (e+f x)\right )}{32 a^3 f}\\ &=\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac {i c^4 \sqrt {c-i c \tan (e+f x)}}{4 a^3 f (c+i c \tan (e+f x))^2}+\frac {i c^3 \sqrt {c-i c \tan (e+f x)}}{16 a^3 f (c+i c \tan (e+f x))}+\frac {\left (i c^3\right ) \text {Subst}\left (\int \frac {1}{2 c-x^2} \, dx,x,\sqrt {c-i c \tan (e+f x)}\right )}{16 a^3 f}\\ &=\frac {i c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{16 \sqrt {2} a^3 f}+\frac {i c^4 (c-i c \tan (e+f x))^{3/2}}{3 a^3 f (c+i c \tan (e+f x))^3}-\frac {i c^4 \sqrt {c-i c \tan (e+f x)}}{4 a^3 f (c+i c \tan (e+f x))^2}+\frac {i c^3 \sqrt {c-i c \tan (e+f x)}}{16 a^3 f (c+i c \tan (e+f x))}\\ \end {align*}
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Mathematica [A]
time = 2.44, size = 152, normalized size = 0.79 \begin {gather*} \frac {c^2 (i \cos (3 (e+f x))+\sin (3 (e+f x))) \left (3 \sqrt {2} \sqrt {c} \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right ) (\cos (3 (e+f x))+i \sin (3 (e+f x)))+\left (9 \cos (e+f x)+5 \cos (3 (e+f x))-44 i \cos ^2(e+f x) \sin (e+f x)\right ) \sqrt {c-i c \tan (e+f x)}\right )}{96 a^3 f} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.34, size = 114, normalized size = 0.59
method | result | size |
derivativedivides | \(\frac {2 i c^{4} \left (\frac {\frac {\left (c -i c \tan \left (f x +e \right )\right )^{\frac {5}{2}}}{32 c}+\frac {\left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{6}-\frac {c \sqrt {c -i c \tan \left (f x +e \right )}}{8}}{\left (c +i c \tan \left (f x +e \right )\right )^{3}}+\frac {\sqrt {2}\, \arctanh \left (\frac {\sqrt {c -i c \tan \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right )}{64 c^{\frac {3}{2}}}\right )}{f \,a^{3}}\) | \(114\) |
default | \(\frac {2 i c^{4} \left (\frac {\frac {\left (c -i c \tan \left (f x +e \right )\right )^{\frac {5}{2}}}{32 c}+\frac {\left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{6}-\frac {c \sqrt {c -i c \tan \left (f x +e \right )}}{8}}{\left (c +i c \tan \left (f x +e \right )\right )^{3}}+\frac {\sqrt {2}\, \arctanh \left (\frac {\sqrt {c -i c \tan \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right )}{64 c^{\frac {3}{2}}}\right )}{f \,a^{3}}\) | \(114\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.51, size = 200, normalized size = 1.04 \begin {gather*} -\frac {i \, {\left (\frac {3 \, \sqrt {2} c^{\frac {7}{2}} \log \left (-\frac {\sqrt {2} \sqrt {c} - \sqrt {-i \, c \tan \left (f x + e\right ) + c}}{\sqrt {2} \sqrt {c} + \sqrt {-i \, c \tan \left (f x + e\right ) + c}}\right )}{a^{3}} + \frac {4 \, {\left (3 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {5}{2}} c^{4} + 16 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}} c^{5} - 12 \, \sqrt {-i \, c \tan \left (f x + e\right ) + c} c^{6}\right )}}{{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{3} a^{3} - 6 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{2} a^{3} c + 12 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )} a^{3} c^{2} - 8 \, a^{3} c^{3}}\right )}}{192 \, c f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 325 vs. \(2 (155) = 310\).
time = 1.41, size = 325, normalized size = 1.68 \begin {gather*} \frac {{\left (3 \, \sqrt {\frac {1}{2}} a^{3} f \sqrt {-\frac {c^{5}}{a^{6} f^{2}}} e^{\left (6 i \, f x + 6 i \, e\right )} \log \left (\frac {{\left (i \, c^{3} + \sqrt {2} \sqrt {\frac {1}{2}} {\left (a^{3} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{3} f\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {c^{5}}{a^{6} f^{2}}}\right )} e^{\left (-i \, f x - i \, e\right )}}{8 \, a^{3} f}\right ) - 3 \, \sqrt {\frac {1}{2}} a^{3} f \sqrt {-\frac {c^{5}}{a^{6} f^{2}}} e^{\left (6 i \, f x + 6 i \, e\right )} \log \left (\frac {{\left (i \, c^{3} - \sqrt {2} \sqrt {\frac {1}{2}} {\left (a^{3} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{3} f\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {c^{5}}{a^{6} f^{2}}}\right )} e^{\left (-i \, f x - i \, e\right )}}{8 \, a^{3} f}\right ) + \sqrt {2} {\left (-3 i \, c^{2} e^{\left (6 i \, f x + 6 i \, e\right )} - i \, c^{2} e^{\left (4 i \, f x + 4 i \, e\right )} + 10 i \, c^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 8 i \, c^{2}\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-6 i \, f x - 6 i \, e\right )}}{96 \, a^{3} f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {i \left (\int \frac {c^{2} \sqrt {- i c \tan {\left (e + f x \right )} + c}}{\tan ^{3}{\left (e + f x \right )} - 3 i \tan ^{2}{\left (e + f x \right )} - 3 \tan {\left (e + f x \right )} + i}\, dx + \int \left (- \frac {c^{2} \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{2}{\left (e + f x \right )}}{\tan ^{3}{\left (e + f x \right )} - 3 i \tan ^{2}{\left (e + f x \right )} - 3 \tan {\left (e + f x \right )} + i}\right )\, dx + \int \left (- \frac {2 i c^{2} \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )}}{\tan ^{3}{\left (e + f x \right )} - 3 i \tan ^{2}{\left (e + f x \right )} - 3 \tan {\left (e + f x \right )} + i}\right )\, dx\right )}{a^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.93, size = 181, normalized size = 0.94 \begin {gather*} \frac {-\frac {c^5\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}\,1{}\mathrm {i}}{4\,a^3\,f}+\frac {c^4\,{\left (c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^{3/2}\,1{}\mathrm {i}}{3\,a^3\,f}+\frac {c^3\,{\left (c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^{5/2}\,1{}\mathrm {i}}{16\,a^3\,f}}{6\,c\,{\left (c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^2-12\,c^2\,\left (c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )-{\left (c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^3+8\,c^3}+\frac {\sqrt {2}\,{\left (-c\right )}^{5/2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}}{2\,\sqrt {-c}}\right )\,1{}\mathrm {i}}{32\,a^3\,f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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